void unionof(int result[], int *count, int set1[], int count1, int set2[], int count2){
 
 int i=0, h=0;
 for(i=0;i<count1;i++){
  result[(*count)++]=set1[i];   
}
 for(h=0;h<count2;h++){
  if(contains(count1, set1, count2, set2[h])==0){
  result[(*count)++]=set2[h];
 }}
}
int contains(int count1, int set1[], int count2, int set2[]){
 int i, found=0;
 for(i=0;i<count1;i++){
   if(set1[i]==set2){
    found=1;
    break;
   } 
 }
 return found;
}
void display(int result[],int count){
 int i;
 printf("{");
 for(i=0;i<count;i++)
  printf("%d,",result[i]);
 printf("\b}\n");
}
About this blog
These codes here are just based on my own knowledge learned from my IT subjects. I know there are more ways that this draft codes can be enhance, so..
Please feel free to comment & suggest.. Suggest Codes which makes my existing codes simpler.. Thanks!
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